Phone interview question # 1: Given an array (for example, [ 1, 0, 2, 0, 0, 3, 4 ]), implement methods that 1. returns the number of non-zero elements (4) 2. moves the non-zero elements to the beginning of the array (the rest of the elements don't matter) -> both [ 1, 2, 3, 4, 0, 0, 0] and [ 4, 1, 3, 2, X, Y, Z ] are valid
Verify that a binary search tree is indeed a binary search tree.
- Given an array, remove the duplicates and return a unique array keeping the first occurrence of the duplicates and the order. [@2, @1, @3, @1, @2] --> [@2, @1, @3] - how would you implement call for canceling queued blocks with dispatch_after?
given an array of words, how to eliminate the duplicates? You have a simple tree structure Ⓐ and its clone ⓐ. Each node in the tree has a pointer to it's parent as well as an array of its children. Given an original tree's node Ⓑ and cloned tree ⓐ, implement a method that returns ⓑ (the clone of Ⓑ). (Imagine finding the matching UIButton/UISlider/UIView in a separate cloned view controller.) Original Ⓐ ┏━┻━━┓ ◯ ◯ ┏┻┓ ┏━╋━┓ ◯ ◯ ◯ ◯ ◯ ┏┻┓ ┃ ◯ Ⓑ ◯ Clone ⓐ ┏━┻━━┓ ◯ ◯ ┏┻┓ ┏━╋━┓ ◯ ◯ ◯ ◯ ◯ ┏┻┓ ┃ ◯ ⓑ ◯
iOS developers have a "dispatch_after(when, queue, block)" Grand Central Dispatch (GCD) function they can utilize but once it's set up, these calls can not be easily cancelled. Describe how you might implement a more convenient version of this named "cancellable_dispatch_after"
Write a function that determines which function is a mirror number. i.e. 12321 would return YES
Can write a function which inputs two ints and check if it is 3 it should return 6 if input is 6 return 3, without using any condition.
Return the head node of the singly linked list with each pair of nodes swapped. If there is a last odd node leave it in place. Example: Input: 1 -> 2 -> 3 -> 4 -> 5 Output: 2 -> 1 -> 4 -> 3 -> 5
How objects can send messages to each other in Objective-C
Flatten a list containing n sublists. Ex: [3, 4, [4, [[55]]]] -> [3, 4, 4, 55]
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